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Let veca = 2hati+hatj, vecb = -hati+3hatj+hatk and vecc = hati+2hatj+5hatk be three vectors. Find (veca-2vecb)xxvecc |
Answer» SOLUTION : = `HATI(-25+4)-HATJ(20+2)+HATK(8+5)` = `-21hati-22hatj+13hatk`. |
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