1.

Let veca=hati+hatj and vecb=2hati-hatk. Then the point of intersection of the lines vecrxxveca=vecbxxveca and vecrxxvecb=vecaxxvecb is (A) (3,-1,10 (B) (3,1,-1) (C) (-3,1,1) (D) (-3,-1,-10

Answer»

`(-1,1,1)`
`(3,-1,1)`
`(3,1,-1)`
`(1,-1,-1)`

ANSWER :C


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