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Let veca,vecb,vecc be three mutually perpendicular vectors having same magnitude and vecr is a vector satisfying vecaxx((vecr-vecb)xxveca)+vecbxx((vecr-vecc)xxvecb)+veccxx((vecr-veca)xxvecb)=vec0, then vecr is equal to |
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Answer» `1/3(veca+vecb+vecc)` |
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