Let x+4y=4 is any straight line. Sum of abscissa and sum of ordinates of the point of intersection of the line with coordinate axes is p and q respectively. Let m be the digit at unit place of the number (p+q)61 and n be the number of integral terms in binomial expansion of (4√9+6√8)500. Then n+m will be

Let x+4y=4 is any straight line. Sum of abscissa and sum of ordinates

1.	Let x+4y=4 is any straight line. Sum of abscissa and sum of ordinates of the point of intersection of the line with coordinate axes is p and q respectively. Let m be the digit at unit place of the number (p+q)61 and n be the number of integral terms in binomial expansion of (4√9+6√8)500. Then n+m will be
Answer» Let $x + 4 y = 4$ is any straight line. Sum of abscissa and sum of ordinates of the point of intersection of the line with coordinate axes is $p$ and $q$ respectively. Let $m$ be the digit at unit place of the number $(p + q)^{61}$ and $n$ be the number of integral terms in binomial expansion of $(\sqrt[4]{9} + \sqrt[6]{8})^{500} .$ Then $n + m$ will be