Let ¯x be the mean of x1,x2,…,xn. and ¯y be the mean of y1,y2…,y

1.	Let ¯x be the mean of x1,x2,…,xn. and ¯y be the mean of y1,y2…,yn If ¯z is the mean of x1,x2,…,xn,y1,y2,…yn, then ¯z=? (a) (¯x+¯y) (b) 12(¯x+¯y) (c) 1n(¯x+¯y) (b) 12n(¯x+¯y)
Answer» Let $¯ x$ be the mean of $x_{1}, x_{2}, \dots, x_{n}$ . and $¯ y$ be the mean of $y_{1}, y_{2} \dots, y_{n}$ If $¯ z$ is the mean of $x_{1}, x_{2}, \dots, x_{n}, y_{1}, y_{2}, \dots y_{n}$ , then $¯ z = ?$ (a) $(¯ x + ¯ y)$ (b) $\frac{1}{2} (¯ x + ¯ y)$ (c) $\frac{1}{n} (¯ x + ¯ y)$ (b) $\frac{1}{2 n} (¯ x + ¯ y)$

Let ¯x be the mean of x1,x2,…,xn. and ¯y be the mean of y1,y2…,yn If ¯z is the mean of x1,x2,…,xn,y1,y2,…yn, then ¯z=? (a) (¯x+¯y) (b) 12(¯x+¯y) (c) 1n(¯x+¯y) (b) 12n(¯x+¯y)

Answer»

Let $¯ x$ be the mean of $x_{1}, x_{2}, \dots, x_{n}$ . and $¯ y$ be the mean of $y_{1}, y_{2} \dots, y_{n}$ If $¯ z$ is the mean of $x_{1}, x_{2}, \dots, x_{n}, y_{1}, y_{2}, \dots y_{n}$ , then $¯ z = ?$

(a) $(¯ x + ¯ y)$

(b) $\frac{1}{2} (¯ x + ¯ y)$

(b) $\frac{1}{2 n} (¯ x + ¯ y)$

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Let ¯x be the mean of x1,x2,…,xn. and ¯y be the mean of y1,y2…,yn If ¯z is the mean of x1,x2,…,xn,y1,y2,…yn, then ¯z=? (a) (¯x+¯y) (b) 12(¯x+¯y) (c) 1n(¯x+¯y) (b) 12n(¯x+¯y)

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