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Let X be the set consisting of the first 2018 terms of the arithmetic progression 1,6,11,⋯, and Y be the set consisting of the first 2018 terms of the arithmetic progression 9,16,23,⋯ . Then, the number of elements in the set X∪Y is

Answer» Let X be the set consisting of the first 2018 terms of the arithmetic progression 1,6,11,, and Y be the set consisting of the first 2018 terms of the arithmetic progression 9,16,23, . Then, the number of elements in the set XY is


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