1.

Let x, p in R, x + 1 gt 0, p ne 0, 1. Then

Answer»

<P>`(1 + X)^(p) gt 1 px "for" p gt 0`
`(1 + x)^(p) gt 1 + px "for" p in (-oo, 0) UU (1, oo)`
`(1 + x)^(p) gt 1 + px "for" 0 lt p lt 1`
`(1 + x)^(p) lt 1 + px "for" p lt 1`

Answer :B


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