Let x1, x2, ..., xn be n observations. Let yi=axi+b for i = 1, 2, 3, ..., n, where a and b are constants. If the mean of xi's is 48 and their standard deviation is 12, the mean of yi's is 55 and standard deviation of yi's is 15, the values of a and b are(a) a = 1.25, b = −5 (b) a = −1.25, b = 5 (c) a = 2.5, b = −5 (d) a = 2.5, b = 5

Let x1, x2, ..., xn be n observations. Let yi=axi+b for i = 1, 2, 3, .

1.	Let x1, x2, ..., xn be n observations. Let yi=axi+b for i = 1, 2, 3, ..., n, where a and b are constants. If the mean of xi's is 48 and their standard deviation is 12, the mean of yi's is 55 and standard deviation of yi's is 15, the values of a and b are(a) a = 1.25, b = −5 (b) a = −1.25, b = 5 (c) a = 2.5, b = −5 (d) a = 2.5, b = 5
Answer» Let x₁, x₂, ..., x_n be n observations. Let $y_{i} = a x_{i} + b$ for i = 1, 2, 3, ..., n, where a and b are constants. If the mean of $x_{i}' s$ is 48 and their standard deviation is 12, the mean of $y_{i}' s$ is 55 and standard deviation of $y_{i}' s$ is 15, the values of a and b are (a) a = 1.25, b = −5 (b) a = −1.25, b = 5 (c) a = 2.5, b = −5 (d) a = 2.5, b = 5

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