Saved Bookmarks
| 1. |
Let \( y=e^{3 x} \) and \( f(x)=-4 e^{-3 x}+e^{6 x} \)i) Find \( f^{\prime}(x) \) and \( f^{\prime \prime}(x) \)ii) Show that \( f^{\prime \prime}(x)=36\left[y^{2}-\frac{1}{y}\right] \) |
|
Answer» f(x) = -4e-3x + e6x f'(x) = 12e-3x + 6e6x f''(x) = -36e-3x + 36e6x = 36(- 1/e3x + (e3x)2) = 36(y2 - 1/y) (∵ y = e3x) |
|