Let y=e{(sin2x+sin4x+sin6x+…)loge2} satisfy the equation x2−17x+16=0, where 0<x<π2. Then match the correct value of List I from List II. List IList II(a)2sin2x1+cos2x(p)1(b)2sinxsinx+cosx(q)49(c)∞∑n=1(cotx)n(r)23(d)∞∑n=1n(cotx)2n(s)43

Let y=e{(sin2x+sin4x+sin6x+…)loge2} satisfy the equation x2−17x+16

1.	Let y=e{(sin2x+sin4x+sin6x+…)loge2} satisfy the equation x2−17x+16=0, where 0<x<π2. Then match the correct value of List I from List II. List IList II(a)2sin2x1+cos2x(p)1(b)2sinxsinx+cosx(q)49(c)∞∑n=1(cotx)n(r)23(d)∞∑n=1n(cotx)2n(s)43
Answer» Let $y = e^{{({sin}^{2} x + {sin}^{4} x + {sin}^{6} x + \dots) {log}_{e} 2}}$ satisfy the equation $x^{2} - 17 x + 16 = 0,$ where $0 < x < \frac{π}{2} .$ Then match the correct value of $List I$ from $List II .$ $\begin{matrix} List I & List II (a) & \frac{2 sin 2 x}{1 + {cos}^{2} x} & (p) & 1 (b) & \frac{2 sin x}{sin x + cos x} & (q) & \frac{4}{9} (c) & \infty \sum n = 1 (cot x)^{n} & (r) & \frac{2}{3} (d) & \infty \sum n = 1 n (cot x)^{2 n} & (s) & \frac{4}{3} \end{matrix}$