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Let y=f(x) be a real-valued differentiable function on the set of all real numbers R such that f(1)=1. If f(x) satisfies xf′(x)=x2+f(x)−2, then the area enclosed by y=f(x) with x-axis between ordinates x=0 and x=3 is |
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Answer» Let y=f(x) be a real-valued differentiable function on the set of all real numbers R such that f(1)=1. If f(x) satisfies xf′(x)=x2+f(x)−2, then the area enclosed by y=f(x) with x-axis between ordinates x=0 and x=3 is |
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