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Let y=mx+c,m>0 be the focal chord of y2=−64x, which is tangent to (x+10)2+y2=4. Then the value of 4√2(m+c) is equal to

Answer» Let y=mx+c,m>0 be the focal chord of y2=64x, which is tangent to (x+10)2+y2=4. Then the value of 42(m+c) is equal to


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