1.

Let y=y(x) be a solution of the differential equation, √1−x2dydx+√1−y2=0,|x|<1. If y(12)=√32, then y(−1√2) is equal to:

Answer»

Let y=y(x) be a solution of the differential equation, 1x2dydx+1y2=0,|x|<1.
If y(12)=32, then y(12) is equal to:



Discussion

No Comment Found