1.

Let y=y(x) be a solution of the differential equation, √1−x2dydx+√1−y2=0,|x|<1.If y(12)=√32, then y(−1√2) is equal to:

Answer»

Let y=y(x) be a solution of the differential equation, 1x2dydx+1y2=0,|x|<1.

If y(12)=32, then y(12) is equal to:



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