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Let y=y(x) be solution of the following differential equation eydydx−2eysinx+sinxcos2x=0, y(π2)=0. If y(0)=loge(α+βe–2), then 4(α+β) is equal to

Answer» Let y=y(x) be solution of the following differential equation eydydx2eysinx+sinxcos2x=0, y(π2)=0. If y(0)=loge(α+βe2), then 4(α+β) is equal to


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