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Let y=y(x) be the solution of the differential equation dydx=(y+1)((y+1)ex2/2−x), 0<x<2.1, with y(2)=0. Then the value of dydxat x=1 is equal to: |
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Answer» Let y=y(x) be the solution of the differential equation dydx=(y+1)((y+1)ex2/2−x), 0<x<2.1, with y(2)=0. Then the value of dydxat x=1 is equal to: |
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