1.

Let y=y(x) be the solution of the differential equation dydx=1+xey−x, −√2<x<√2, y(0)=0, then the minimum value of y(x), x∈(−√2,√2) is equal to

Answer»

Let y=y(x) be the solution of the differential equation dydx=1+xeyx, 2<x<2, y(0)=0, then the minimum value of y(x), x(2,2) is equal to




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