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Let y=y(x) be the solution of the differential equation, xdydx+y=xlogex,(x>1). If 2y(2)=loge4−1, then y(e) is equal to: |
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Answer» Let y=y(x) be the solution of the differential equation, xdydx+y=xlogex,(x>1). If 2y(2)=loge4−1, then y(e) is equal to: |
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