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Let y=y(x) be the solution of the differential equation, dydx+ytanx=2x+x2tanx, x∈(−π2,π2), such that y(0)=1. Then : |
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Answer» Let y=y(x) be the solution of the differential equation, dydx+ytanx=2x+x2tanx, x∈(−π2,π2), such that y(0)=1. Then : |
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