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Let y=y(x) be the solution of the differential equaiton cosec2xdy+2dx=(1+ycos2x)cosec2xdx, with y(π4)=0. Then, the value of (y(0)+1)2 is equal to: |
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Answer» Let y=y(x) be the solution of the differential equaiton cosec2xdy+2dx=(1+ycos2x)cosec2xdx, with y(π4)=0. Then, the value of (y(0)+1)2 is equal to: |
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