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Let z=1−i√32, i=√−1. Then the value of 21+(z+1z)3+(z2+1z2)3+(z3+1z3)3+⋯+(z21+1z21)3 is

Answer» Let z=1i32, i=1. Then the value of 21+(z+1z)3+(z2+1z2)3+(z3+1z3)3++(z21+1z21)3 is


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