1.

Let z be a complex number lying oon a circle |z|=sqrt(2) a and b=b_(1)+ib_(2) (any complex number), then The equation of lines passing through the centre of the circle and making an angle (pi)/(4), with the normal at 'b' are

Answer»

`Z=+-(lb^(2))/(2a^(2))BAR(z)`
`z=+-(ib^(2))/(a^(2))bar(z)`
`z=+-(ib^(2))/(3A^(2))bar(z)`
`z=+-(ib^(2))/(4a^(2))bar(z)`

Answer :A


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