Let `z`be a complex number satisfying equation `z^p-z^(-q),w h e r ep ,q in N ,t h e n`if `p=q`, then number of solutions of equation will be infinite.if `p=q`, then number of solutions of equation will be finite.if `p!=q`, then number of solutions of equation will be `p+q+1.`if `p!=q`, then number of solutions of equation will be `p+qdot`A. if p=q, then number of solution of equation will infinte.B. if p=q, then number of solutions of equaiton will finiteC. if `pne q`, then number of solutions of equaiton will `p+q+1`.D. if `p ne q`, then number of solutions of equaiton will be `p+q`

Let `z`be a complex number satisfying equation `z^p-z^(-q),w h e r ep

1.	Let `z`be a complex number satisfying equation `z^p-z^(-q),w h e r ep ,q in N ,t h e n`if `p=q`, then number of solutions of equation will be infinite.if `p=q`, then number of solutions of equation will be finite.if `p!=q`, then number of solutions of equation will be `p+q+1.`if `p!=q`, then number of solutions of equation will be `p+qdot`A. if p=q, then number of solution of equation will infinte.B. if p=q, then number of solutions of equaiton will finiteC. if `pne q`, then number of solutions of equaiton will `p+q+1`.D. if `p ne q`, then number of solutions of equaiton will be `p+q`
Answer» Correct Answer - A::B If q=p, then equation becomes `z^(p)= z^(-q)` and it has infinte number of solutions because any z `in ` R will satisfly it. `p ne q`, let `p gt q`, then `z^(p) = z^(-q)`

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