InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Let `z`be a complex number satisfying the equation `z^3-(3+i)z+m+2i=0,w h e r em in Rdot`Suppose the equation has a real root. Then root non-real root. |
|
Answer» Let`alpha` be the root . Then, `alpha^(2) -(3+ i)alpha + m + 2i = 0` `rArr (alpha ^(2) - 3alpha + m) + i(2-alpha)=0` `rArr alpha^(2) - 3 alpha +m = 0 and 2-alpha =0` `rArr alpha = 2 and m =2` Product of the roots is 2(1+i) with one roots as 2. Hence, the nonreal roots is 1+i. |
|