1.

Letalpha(n)=1-(1)/(2)+(1)/(3)-(1)/(4)+.........+(-1)^(n-1)(1)/(n),ninN, then

Answer»

`(1)/(n+1)+(1)/(n+2)+.........+(1)/(2n)=ALPHA(2n)`
`alpha(2n)lt1AAninN`
`alpha(2n)ge(1)/(2)AAninN`
`alpha(n)GT(1)/(2)AAninN`

Answer :A::B::C


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