1.

Letf(x)=x^(2)+bx+c, where b, c inRIf f (x) is a factor of both x^(4)+6x^(2)+25and3x^(4)+4x^(2)+28x+5.then the least value of f (x) is

Answer»


SOLUTION :`f(X)` will also be a factor of `3(x^(4)+6X^(2)+25)-(3x^(4)+4x^(2)+28+5)`. Which EQUALS `14(x^(2)-2x+5)`.
So, `f(x)=x^(2)-2x+5 le 4`


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