LEVEL 1EXERCIA1. In a A ABC, if ZA = 55°, ZB = 40", find ZC.. If the

1.	LEVEL 1EXERCIA1. In a A ABC, if ZA = 55°, ZB = 40", find ZC.. If the anelor of
Answer» Sum of All ∠ of Triangle = 180 Given ∠A= 55 ∠ B = 40 Therefore, ∠A + ∠B + ∠C = 180 55 + 40 + ∠C = 180 95 + ∠C= 180 ∠C = 180 - 95 ∠C = 85 simple add the angle a and b you give the answer of c sum of interior angles in a triangle =180° <A+<B+<C=180[Angle sum property] 55+40+<c=180<C=180-95<C=85. A+B+C=180'55'+40'+C=180'95'+C=180'C=180'-95'C=85' the sum of all angle is =180 so angle a +b =180 40+55=18095=180taking 95 on right side 180-9585

LEVEL 1EXERCIA1. In a A ABC, if ZA = 55°, ZB = 40", find ZC.. If the anelor of

Answer»

Sum of All ∠ of Triangle = 180 Given ∠A= 55 ∠ B = 40

Therefore, ∠A + ∠B + ∠C = 180 55 + 40 + ∠C = 180 95 + ∠C= 180 ∠C = 180 - 95 ∠C = 85

simple add the angle a and b you give the answer of c

sum of interior angles in a triangle =180°

<A+<B+<C=180[Angle sum property]

55+40+<c=180<C=180-95<C=85.

A+B+C=180'55'+40'+C=180'95'+C=180'C=180'-95'C=85'

the sum of all angle is =180 so angle a +b =180 40+55=18095=180taking 95 on right side 180-9585