InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
`Li` forms a body-centred cubic lattice. If the edge of the cube is `3.5 xx 10^(-10)m` and the density is `5.3 xx 10^(2) kg m^(-3)`, calculate the percentage occupancy of `Li` metal. |
|
Answer» `= (Z_(eff) xx Aw)/(N_(A) xx a^(3)) = (2 xx 7 xx 10^(-3))/(6.023 xx 10^(23) xx (3.5 xx 10^(10))^(3))` `= 5.4 xx 10^(2) kg m^(-3)` Percentage occupancy `= (5.3 xx 10^(2))/(5.4 xx 10^(2)) xx 100 = 98%` |
|