1.

Lifetimesof themoleculesin theexcitedstatesare oftenmeasuredby usingpulsedradiationsourceof durationnearlyin the nanosecondrange. If theradiationsourcehas theemittedduringthe pulsesourceis 2.5 xx 10^(15).Calculatethe energyof the source .

Answer»

Solution :radiationduration`=2 ns = 2 xx 10^(9) s`
Frequency= `(1) /(" radiation period") = (1)/( 2xx 10^(9) s)`
total= NOOF photon(N ) `xx ` energyof 1photon(hv )E = Nhv
`=(2.5 xx 10^(15) )(1.626 xx 10^(34) J s) (5.0 xx 10^(8) s)`
`=82 .825 xx 10^(11) J`
`=8.282xx 10^(10)J`


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