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Lifetimesof themoleculesin theexcitedstatesare oftenmeasuredby usingpulsedradiationsourceof durationnearlyin the nanosecondrange. If theradiationsourcehas theemittedduringthe pulsesourceis 2.5 xx 10^(15).Calculatethe energyof the source . |
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Answer» Solution :radiationduration`=2 ns = 2 xx 10^(9) s` Frequency= `(1) /(" radiation period") = (1)/( 2xx 10^(9) s)` total= NOOF photon(N ) `xx ` energyof 1photon(hv )E = Nhv `=(2.5 xx 10^(15) )(1.626 xx 10^(34) J s) (5.0 xx 10^(8) s)` `=82 .825 xx 10^(11) J` `=8.282xx 10^(10)J` |
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