Light in incident on a metal plate whose work function is 2 eV. Electric field associated with light is given by `E=E_(0)sin(omegat-(2pi)/(5xx10^(7))x)`{ S.I unit} if energy of photom is given by `(12375)/(lamda("in"A))` eV then stopping potential isA. `2.48eV`B. `0.48eV`C. `0.78eV`D. `1.24eV`

Light in incident on a metal plate whose work function is 2 eV. Electr

1.	Light in incident on a metal plate whose work function is 2 eV. Electric field associated with light is given by `E=E_(0)sin(omegat-(2pi)/(5xx10^(7))x)`{ S.I unit} if energy of photom is given by `(12375)/(lamda("in"A))` eV then stopping potential isA. `2.48eV`B. `0.48eV`C. `0.78eV`D. `1.24eV`
Answer» Correct Answer - B

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Light in incident on a metal plate whose work function is 2 eV. Electric field associated with light is given by `E=E_(0)sin(omegat-(2pi)/(5xx10^(7))x)`{ S.I unit} if energy of photom is given by `(12375)/(lamda("in"A))` eV then stopping potential isA. `2.48eV`B. `0.48eV`C. `0.78eV`D. `1.24eV`

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