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Light is incident on a polarizer with intensity `I_0`. A second prism called analyzer is kept at a angle of `15^@`, from the first polarizer then the intensity of final emergent light will be A. (a) `0.5I_0`B. (b) `0.3I_0`C. (c) `0.46I_0`D. (d) `0.83I_0` |
Answer» Correct Answer - C `I=I_0/2cos^2(15^@)` `I=I_0/4*2cos^2(15^@)` `I=I_0/4[1+cos(30^@)]` `I=I_0/4*[1+sqrt3/2]` `I=I_0/8[2+sqrt3]` `I=0.46I_0` |
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