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Light of wavelength `400nm` is incident continuously on a Cesium ball. (work function `1.9eV`). The maximum potential to which the ball will be charged isA. 3.1VB. 1.2 VC. zeroD. infinite |
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Answer» (B) `eV_(s) =(hc)/(lambda)-phi=(1240(nm)eV)/(400(nm))-1.9 eV=1.2 eV` `implies V_(s)=1.2 V` `:.` The cesuim ball can be charged to a maximum potential of 1.2 V |
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