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Light of wavelength `500nm` in medium A enters into medium B through a plane surface. If frequency of light is `4xx10^(14)Hz` and `v_A//v_B=4//5`, find absolute refractive indices of media A and B. |
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Answer» `v_A=upsilonlambda_A=4xx10^(14)xx500xx10^-9=2xx10^8 m//sec` `mu_A=(c)/(v_A)=(3xx10^8)/(2xx10^8)=3/2` `muprop1/v` `(mu_A)/(mu_B)=(v_B)/(v_A)implies(3//2)/(mu_B)=5/4` `mu_B=0.8xx1.5=1.2` |
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