1.

Light with an enargy flux of `25xx10^(4) Wm^(-2)` falls on a perfectly reflecting surface at normal incidence. If the surface area is `15 cm^(2)`, the average force exerted on the surface isA. `1.25xx10^-6N`B. `2.50xx10^-6N`C. `1.20xx10^-6N`D. `3.0xx10^-6N`

Answer» Correct Answer - b
Average force =average pressurexxarea
`:. F_(av)=(2I)/cxxA=(2xx(25xx10^4)xx(15xx10^-4))/(3xx10^8)`
`=2.5xx10^-6N`


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