1.

lim_(x to 0) ((2^x +3^x + 6^x )/3)^(3//x) is equal to :

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Solution :Given limit is of the form `(1)^OO`
`L=E^("LIM"_(x to 0)) (2^x log 2+3^x log 3+6^x log 6)/1`
`L=e^(log (2xx3xx6)) = e^(log 36) =36`


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