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lim_(xto-2)[x] |
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Answer» SOLUTION :L.H.L.`=lim_(xto-2-)(x-2)/|x-2|` `=lim_(hto0)[-2-h]=-3` R.H.L.`=lim_(xto-2+)[x]=lim_(hto0)[-2+h]=-2` Thus `L.H.L.neR.H.L.` So the limit does not exist. |
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