1.

lim_(xto-2)[x]

Answer»

SOLUTION :L.H.L.`=lim_(xto-2-)(x-2)/|x-2|`
`=lim_(hto0)[-2-h]=-3`
R.H.L.`=lim_(xto-2+)[x]=lim_(hto0)[-2+h]=-2`
Thus `L.H.L.neR.H.L.`
So the limit does not exist.


Discussion

No Comment Found

Related InterviewSolutions