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lim_(xto0) |x| |
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Answer» Solution :We see that when `xto0, |x|to0` Let US establish this using `EPSILON-delta` technique. Let `epsilongt0` we seek a `deltagt0` DEPENDING on `epsilons.t. |x-0|epsilon implies||x|-0|let epsilon` Now `||x|-o|=||x||=|x|ltdelta` Choosing `epsilon=delta` we have `|x|topsoil implies||x|-0|ltepsilon` `therefore lim_(xto0)|x|=0` |
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