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lim_(xto0)|x|/x |
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Answer» SOLUTION :L.H.L.`=lim_(xto0-)|x|/x` `=lim_(hto0)([0-h])/(0-h)=lim_(hto0)h/(-h)=-1` R.H.L.`=lim_(xto0+)([x])/x=lim_(hto0)([0+h])/(|0+h|)=1` As `L.H.L.neR.H.L.,` So the LIMIT does not EXIST. |
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