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lim_(xto2)(x-2)/(|x-2|) |
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Answer» SOLUTION :L.H.L.`=lim_(hto0)(2-h-2)/(|2-h-2)|` `=lim_(hto0)(-h)/(|-h|)=lim_(hto0)(-h)/h=-1` R.H.L.`=lim_(hto0)(2+h-2)/(2+h-2)=lim_(hto0)(h)/(|h|)=1` As `L.H.LneR.H.L.` the LIMIT does not EXIST. |
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