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lim_(xtosqrt3)[x] |
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Answer» SOLUTION :L.H.L.`=lim_(xtosqrt3-)[X]=lim_(hto0)[sqrt3-h]=1` R.H.L.`=lim_(xtosqrt3+)[x]=lim_(hto0)[sqrt3+h]=1` Thus L.H.L., R.H.L. both EXIST and L.H.L.=R.H.L. So the limit exists and it's value is 1. |
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