1.

limh→02⎧⎪⎨⎪⎩√3sin(π6+h)−cos(π6+h)√3h(√3cosh−sinh)⎫⎪⎬⎪⎭ is equal to

Answer»

limh→02⎧⎪⎨⎪⎩√3sin(π6+h)−cos(π6+h)√3h(√3cosh−sinh)⎫⎪⎬⎪⎭ is equal to




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