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limx>0 x^10-1024/x^5-32 |
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Answer» please write it on a paper and post it x^10 - 1024 = (x^5)^2 - (2^5)^2 = (x^5 - 2^5 )(x^5 + 2^5) so given term = lim x tends to 0 (x^5 - 2^5 )(x^5 + 2^5) /(x^5 - 2^5 ) = lim x tends to 0 (x^5 + 2^5) = 2^5 please write on paper i cannot understand it please |
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