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Line xa+yb=1 cuts the coordinate axes at A (a, 0) and B(0, b) and the line xa′+yb′=−1 at A' (-a', 0) and B' (0, -b'). If the point A, B, A', B' are concyclic then the orthocenter of the triangle ABA' is |
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Answer» Line xa+yb=1 cuts the coordinate axes at A (a, 0) and B(0, b) and the line xa′+yb′=−1 at A' (-a', 0) and B' (0, -b'). If the point A, B, A', B' are concyclic then the orthocenter of the triangle ABA' is |
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