1.

lines XY and MN intersect at O. f90° anda :b2:3, find c.Fig6.14

Answer»

Given,

∠POY= 90° &

a : b = 2 : 3

A.T.Q

∠POY+∠POX =180°

[By linear pair axiom]

∠POY+a + b = 180°⇒90° + a + b = 180°⇒a + b = 90°

Let a = 2x & b= 3x

2x + 3x = 90°⇒5x = 90°⇒x = 18°

∴a = 2×18° = 36°

b = 3×18° = 54°

Now, OX is a ray on the line MON.

∠XOM+ ∠XON=180°

b + c = 180° (by Linear Pair axiom)⇒54° + c = 180°⇒c = 126°

The value of c =126°

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