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lines XY and MN intersect at O. f90° anda :b2:3, find c.Fig6.14 |
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Answer» Given, ∠POY= 90° & a : b = 2 : 3 A.T.Q ∠POY+∠POX =180° [By linear pair axiom] ∠POY+a + b = 180°⇒90° + a + b = 180°⇒a + b = 90° Let a = 2x & b= 3x 2x + 3x = 90°⇒5x = 90°⇒x = 18° ∴a = 2×18° = 36° b = 3×18° = 54° Now, OX is a ray on the line MON. ∠XOM+ ∠XON=180° b + c = 180° (by Linear Pair axiom)⇒54° + c = 180°⇒c = 126° The value of c =126° Like my answer if you find it useful! |
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