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Liquid is flowing throgh a tube of nonuniform cross section ratio of the radius at entry a and exit end B of the tube is 3 :2. Then the ratio of velocities at entry A and exit B of liquid is …… |
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Answer» `4:9` `(v_(A))/(v_(B))=?` According to EQUATION of CONTINUITY, `A_(A)v_(A)=A_(B)v_(B)` `(v_(A))/(v_(B))=(A_(B))/(A_(A))=(pir_(B)^(2))/(PIRA^(2))` `therefore(v_(A))/(v_(B))=((r_(B))/(r_(A)))^(2)=((2)/(3))^(2)` `(v_(A))/(v_(B))=(4)/(9)` |
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