1.

Liquid is flowing throgh a tube of nonuniform cross section ratio of the radius at entry a and exit end B of the tube is 3 :2. Then the ratio of velocities at entry A and exit B of liquid is ……

Answer»

`4:9`
`9:4`
`8:27`
`1:1`

Solution :`(r_(A))/(r_(B))=(3)/(2)`
`(v_(A))/(v_(B))=?`
According to EQUATION of CONTINUITY,
`A_(A)v_(A)=A_(B)v_(B)`
`(v_(A))/(v_(B))=(A_(B))/(A_(A))=(pir_(B)^(2))/(PIRA^(2))`
`therefore(v_(A))/(v_(B))=((r_(B))/(r_(A)))^(2)=((2)/(3))^(2)`
`(v_(A))/(v_(B))=(4)/(9)`


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