Liquid water freezes at 273K under external pressure of 1 atm. The process is at equilibrium H_(2)O (l) hArr H_(2)O (s) at 273 K & 1 atm. However it was required to calculate the thermodynamic parameters of the fusion process occuring at same pressure & different temperature.Using the following data, answer the question that follow. d_("ice") = 0.9 gm/cc, d_(H_(2)O(l)) = 1 gm//c, C_(P) [H_(2)O(s))] = 36.4 JK^(-1) mol^(-1) C_(P) [H_(2)O(l)] = 75.3 JK^(-1) mol^(-1), Delta H_("fusion") = 6008.2 J mol^(-1) The value of ''Delta H_("fusion")'' at 263K & 1 atm will be

Liquid water freezes at 273K under external pressure of 1 atm. The pro

1.	Liquid water freezes at 273K under external pressure of 1 atm. The process is at equilibrium H_(2)O (l) hArr H_(2)O (s) at 273 K & 1 atm. However it was required to calculate the thermodynamic parameters of the fusion process occuring at same pressure & different temperature.Using the following data, answer the question that follow. d_("ice") = 0.9 gm/cc, d_(H_(2)O(l)) = 1 gm//c, C_(P) [H_(2)O(s))] = 36.4 JK^(-1) mol^(-1) C_(P) [H_(2)O(l)] = 75.3 JK^(-1) mol^(-1), Delta H_("fusion") = 6008.2 J mol^(-1) The value of ''Delta H_("fusion")'' at 263K & 1 atm will be
Answer» `+6008.2 J "mole"^(-1)` `5619.2 J "mole"^(-1)` `-5619.2 J "mole"^(-1)` `6619.2 J "mole"^(-1)` Solution :`Delta H_("FUSION")` at 263and 1 atm will be occurred as follows: `"ice"_(263K) rarr "ice"_(273K) rarr H_(2)O_((L)_(273)) rarr H_(2)O_((l) 263)` So `Delta H_("fusion")` at 263K = `Cp_("ice") xx Delta T + Delta H_("fusion")` at `273- CP_(H_(2)O). Delta T` `= 36.4 xx 10 + 6008.2 - 75.3 xx 10` =5619.2 J/mole