Liquid water freezes at 273K under external pressure of 1 atm. The process is at equilibrium H_(2)O (l) hArr H_(2)O (s) at 273 K & 1 atm. However it was required to calculate the thermodynamic parameters of the fusion process occuring at same pressure & different temperature.Using the following data, answer the question that follow. d_("ice") = 0.9 gm/cc, d_(H_(2)O(l)) = 1 gm//c, C_(P) [H_(2)O(s))] = 36.4 JK^(-1) mol^(-1) C_(P) [H_(2)O(l)] = 75.3 JK^(-1) mol^(-1), Delta H_("fusion") = 6008.2 J mol^(-1) ''DeltaS_("fusion")'' at 263 K & 1 atm will be

Liquid water freezes at 273K under external pressure of 1 atm. The pro

1.	Liquid water freezes at 273K under external pressure of 1 atm. The process is at equilibrium H_(2)O (l) hArr H_(2)O (s) at 273 K & 1 atm. However it was required to calculate the thermodynamic parameters of the fusion process occuring at same pressure & different temperature.Using the following data, answer the question that follow. d_("ice") = 0.9 gm/cc, d_(H_(2)O(l)) = 1 gm//c, C_(P) [H_(2)O(s))] = 36.4 JK^(-1) mol^(-1) C_(P) [H_(2)O(l)] = 75.3 JK^(-1) mol^(-1), Delta H_("fusion") = 6008.2 J mol^(-1) ''DeltaS_("fusion")'' at 263 K & 1 atm will be
Answer» `22.01 JK^(-1) mol^(-1)` `22.84 JK^(-1) mol^(-1)` `21.36 JK^(-1) mol^(-1)` `20.557 KJ^(-1) mol^(-1)` SOLUTION :`Delta S_("fusion")` at 263K `= (Delta H_("fusion") " at " 263)/(263) = 21.365 Jk^(-1) "MOLE"^(-1)`