{:(,"List I ( Equations)",,"List II( Type of Processes)"),((A),K_(p) gt Q ,(p),"Non-spontaneous"),((B ),DeltaG^(@) lt RT ln Q,(q ),"Equilibrium "),((C),K_(p) =Q ,(r),"Spontaneous and endothermic "),((D),T gt (DeltaH)/( DeltaS),(s),"Spontaneous"):} (a) A-p,B-q,C-r,D-s(b) A-r,B-s,C-q,D-p(c ) A-s,B-p,C-q,D-r(d) A-q,B-p,C-s,D-r

{:(,"List I ( Equations)",,"List II( Type of Processes)"),((A),K_(p) g

1.	{:(,"List I ( Equations)",,"List II( Type of Processes)"),((A),K_(p) gt Q ,(p),"Non-spontaneous"),((B ),DeltaG^(@) lt RT ln Q,(q ),"Equilibrium "),((C),K_(p) =Q ,(r),"Spontaneous and endothermic "),((D),T gt (DeltaH)/( DeltaS),(s),"Spontaneous"):} (a) A-p,B-q,C-r,D-s(b) A-r,B-s,C-q,D-p(c ) A-s,B-p,C-q,D-r(d) A-q,B-p,C-s,D-r
Answer» Solution :(A) `K_(p) gt Q` or`Q lt K_(p0` means that the reaction will PROCEED in the forward DIRECTION, i.e., reaction is SPONTANEOUS .Hence, `Ararr(s)` (B)`DeltaG= DeltaG^(@) + RT ln Q` At equilibrium , `DeltaG=0, Q=K`. Hence, `DeltaG^(@) = - RT ln K` `:. DeltaG^(@) = - RT ln K( i.e., DeltaG^(@)0 + RT ln Q` When `DeltaG^(@)lt RT ln Q, Delta G` is `+ve`. Therefore, forward reaction is non-spontaneous. Hence,`B rarr (p)` ,brgt (C ) `K_(p) = Q` means that the reaction is in equilibrium . Hence, `C rarr (q)`. (D ) `T gt(DELTAH)/(DeltaS)` means `T DeltaS gt DeltaH ` . As`DeltaG = DeltaH-T DeltaS` Hence,reaction is spontaneous, i.e.,`DeltaG ` is -ve only when `DeltaH` is `+ve` . Hence, `D rarr( r )`.