List I has four entries and List II has five entries. Each entry of List I is to be correctly matched with one or more than one entries of List II. List IList II (A)Let f:A→B be a function defined by (P)−1 f(x)=log(x2−7|x|+12). If C=Z−A is a set, then an element in C is (B)A solution of the inequation(Q)0∣∣∣2x−4∣∣∣>1 is(C)If f(x)=log(1−|x||x−2|), then an(R)1integer which is not in the domainof f, is(D)An element in the domain of the (S)2function f(x)=ex−4x2√4x−x2 is(T)3Which of the following is the only CORRECT combination?

List I has four entries and List II has five entries. Each entry of Li

1.	List I has four entries and List II has five entries. Each entry of List I is to be correctly matched with one or more than one entries of List II. List IList II (A)Let f:A→B be a function defined by (P)−1 f(x)=log(x2−7\|x\|+12). If C=Z−A is a set, then an element in C is (B)A solution of the inequation(Q)0∣∣∣2x−4∣∣∣>1 is(C)If f(x)=log(1−\|x\|\|x−2\|), then an(R)1integer which is not in the domainof f, is(D)An element in the domain of the (S)2function f(x)=ex−4x2√4x−x2 is(T)3Which of the following is the only CORRECT combination?
Answer» $List I$ has four entries and $List II$ has five entries. Each entry of $List I$ is to be correctly matched with one or more than one entries of $List II .$ $\begin{matrix} List I & List II (A) & Let f : A \to B be a function defined by & (P) & - 1 f (x) = log (x^{2} - 7 \| x \| + 12) . If C = Z - A is a set, then an element in C is (B) & A solution of the inequation & (Q) & 0 ∣ ∣ ∣ \frac{2}{x - 4} ∣ ∣ ∣ > 1 is (C) & If f (x) = log (\frac{1 - \| x \|}{\| x - 2 \|}), then an & (R) & 1 integer which is not in the domain of f, is (D) & An element in the domain of the & (S) & 2 function f (x) = \frac{e^{x - 4 x^{2}}}{\sqrt{4 x - x^{2}}} is (T) & 3 \end{matrix}$ Which of the following is the only CORRECT combination?