{:("List-I","List-II"),((A) 1xx10^(-8) "M KOH",P.pH=1.3),((B)1xx10^(-8)"MHBr" ,Q.pH=6.95),((C )1"MHCI"+1 "MNaOH",R.pH=7.0414),((D) 0.02 MH_(2)SO_(4),S.pH=7),(,"acidic solution"):}

{:("List-I","List-II"),((A) 1xx10^(-8) "M KOH",P.pH=1.3),((B)1xx10^(-8

1.	{:("List-I","List-II"),((A) 1xx10^(-8) "M KOH",P.pH=1.3),((B)1xx10^(-8)"MHBr" ,Q.pH=6.95),((C )1"MHCI"+1 "MNaOH",R.pH=7.0414),((D) 0.02 MH_(2)SO_(4),S.pH=7),(,"acidic solution"):}
Answer» Solution :KOH is basic ,HBr is acidic ` HCl + NAOH ` complete NEUTRALISATION ` 0.02 M H_2SO_4 RARR [H^(+) ] =0.04 ` ` rArr pH = 2 - log 4 = 1.4`