{:("List-I","List-II"),((A) 1xx10^(-8) "M KOH",P.pH=1.3),((B)1xx10^(-8)"MHBr" ,Q.pH=6.95),((C )1"MHCI"+1 "MNaOH",R.pH=7.0414),((D) 0.02 MH_(2)SO_(4),S.pH=7),(,"acidic solution"):}

{:("List-I","List-II"),((A) 1xx10^(-8) "M KOH",P.pH=1.3),((B)1xx10^(-8

1.	{:("List-I","List-II"),((A) 1xx10^(-8) "M KOH",P.pH=1.3),((B)1xx10^(-8)"MHBr" ,Q.pH=6.95),((C )1"MHCI"+1 "MNaOH",R.pH=7.0414),((D) 0.02 MH_(2)SO_(4),S.pH=7),(,"acidic solution"):}
Answer» <html><body><p><br/></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/koh-528424" style="font-weight:bold;" target="_blank" title="Click to know more about KOH">KOH</a> is basic ,HBr is acidic<br/> ` HCl + <a href="https://interviewquestions.tuteehub.com/tag/naoh-572531" style="font-weight:bold;" target="_blank" title="Click to know more about NAOH">NAOH</a> ` complete <a href="https://interviewquestions.tuteehub.com/tag/neutralisation-577399" style="font-weight:bold;" target="_blank" title="Click to know more about NEUTRALISATION">NEUTRALISATION</a> <br/> ` 0.02 M H_2SO_4 <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> [H^(+) ] =0.04 ` <br/> ` rArr pH = <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> - log 4 = 1.4`</body></html>